Two ideal diodes are connected to a battery a | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) In the given circuit,the upper diode $D_1$ is forward-biased because its p-side is connected to the positive terminal of the battery.The lower dio

Vedclass · Accepted Answer

$0.5$

Vedclass · Answer

(D) In the given circuit,the upper diode $D_1$ is forward-biased because its p-side is connected to the positive terminal of the battery.The lower diode $D_2$ is reverse-biased because its n-side is connected to the positive terminal of the battery.An ideal diode in forward bias acts as a short circuit (zero resistance),and an ideal diode in reverse bias acts as an open circuit (infinite resistance).Therefore,no current flows through the branch containing $D_2$.The total current supplied by the battery flows only through the branch containing $D_1$ and the $10 \ \Omega$ resistor.Using Ohm's law,$I = \frac{V}{R} = \frac{5 \ V}{10 \ \Omega} = 0.5 \ A$.

Two ideal diodes are connected to a battery as shown in the circuit. The current supplied by the battery is......$A$

Similar Questions

For the given circuit of a $PN-$ junction diode,which of the following statements is correct?

Which of the following statements is not correct when a junction diode is in forward bias?

$A$ circuit and the signal applied at its input terminal $(V_i)$ are shown in the figure below. Which one of the options correctly describes the output waveform $(V_0)$? (Assume all the devices used are ideal and take $P$ as the reference potential.)

Barrier potential of a $p-n$ junction diode does not depend on:

For an ideal diode,the current in the following arrangement is:

Vedclass Test Series

Exam Paper Generator

Online Exam Module